If the product of two consecutive even integers is 288, how do you find the integers?

$288 = \left(n - 1\right) \left(n + 1\right) = {n}^{2} - {1}^{2} = {n}^{2} - 1$
[[ using the difference of squares identity ${a}^{2} - {b}^{2} = \left(a - b\right) \left(a + b\right)$ ]]
Then ${n}^{2} = 288 + 1 = 289 = {17}^{2}$
So $n = \pm \sqrt{{17}^{2}} = \pm 17$