# If the reaction of 20.7 grams of CaCO3 produces 6.81 grams of CaO, what is the percent yield? CaCO3=>CaO+CO2

Jul 20, 2014

CaC${O}_{3}$ --------> CaO + C${O}_{2}$

20.7 g 6.81g +

As per the law of Conservation of mass , in any chemical reaction, the total mass of products is equal to the total mass of the reactants.

mass of C${O}_{2}$ + mass of CaO is equal to the mass of CaC${O}_{3}$ .

mass of C${O}_{2}$ + 6.81g = 20.7g

mass of C${O}_{2}$ = 20.7g- 6.81g = 13.89g

% yield of a Product Z = mass of product Z x 100 / mass of reactant

% yield of Product C${O}_{2}$ = 13.89 x 100 / 20.7 = 67. 10%

% yield of Product CaO = 6.81g x 100 /20.7 = 32.89%