If the roots of equation #x^2 + qx + p=0# are each 1 less than the roots of the equation #x^2 + px + q = 0# then #(p+q)# is equal to?
2 Answers
given that the roots of equation
Let the roots of the equation
So we can write
again
Comparing we get
and
By {1] and [2]
Now from first two relations
Explanation:
Assuming
and comparing coefficients we get
now calling
Solving
hence