Question

If the sum of the measures of the interior angles of a polygon is 5400°, how many sides does it have?

Answer 1

`32`

Explanation:

Let `S` be the sum of the interior angles of the polygon,

`=> S=(n-2)*180^@`,
where `n` is the number of sides.

Given `S=5400^@`
`=> 5400=(n-2)*180`
`=> n-2=5400/180=30`
`=> n=32`

Hence, the polygon has 32 sides.