If the sum of the measures of the interior angles of a polygon is 5400°, how many sides does it have?

1 Answer
Apr 11, 2017

Answer:

#32#

Explanation:

Let #S# be the sum of the interior angles of the polygon,

#=> S=(n-2)*180^@#,
where #n# is the number of sides.

Given #S=5400^@#
#=> 5400=(n-2)*180#
#=> n-2=5400/180=30#
#=> n=32#

Hence, the polygon has 32 sides.