# If the sum of the squares of two consecutive integers is 41, how do you find the integers?

Jun 3, 2015

We are looking for two consecutive integers whose squares sum up to 41.

A consecutive integer means that one integer comes directly after the other, or is just added to 1.

We know that ${4}^{2} = 16$
We also know that ${5}^{2} = 25$
Since $16 + 25 = 41$, our two numbers must be $4$ and $5$.