If the tangent line to y=f(x) at (3,7) passes through the point (1,-3), how do you find f'(3)?
1 Answer
May 26, 2017
Explanation:
#"using " f'(x)=m_(color(red)"tangent")" at " x=a#
#rArrm_(color(red)"tangent")=(7+3)/(3-1)=5larr" gradient formula"#
#"the tangent at " (3,7)tox=3" is "#
#f'(3)=5#
