Question

If the total revenue function for a hammer is `R=36x-.01x^2`, then sale of how many hammers, `x`, will maximize the total revenue in dollars?

Answer 1

I got `1800` hammers or `$32400`

Explanation:

We can derive our function and set it equal to zero. This will give us a max or min (in this case I know it is a max) and the corresponding `x` value:
so
`R'=36-0.02x`
set it equal to zero:
`36-0.02x=0`
rearrange:
`x=36/0.02=1800` hammers