# If the volume of a container of gas is reduced, what will happen to the pressure inside the container?

Nov 28, 2016

At constant $\text{temperature, } {P}_{1} {V}_{1} = {P}_{2} {V}_{2}$, which is $\text{Boyle's law}$ and so.........

#### Explanation:

Pressure varies as the ratio ${V}_{1} / {V}_{2}$. If the gas were enclosed in a piston, the pressure should increase as the piston is compressed, and the pressure should decrease as the piston expands. This is intuitively sound.

Of course, we can combine with $\text{Charles' Law}$ to give $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$, the combined gas law, and with $\text{Avogadro's law}$, $V \propto n$, to give the Ideal Gas law, $P V = n R T$, for an ideal gas.