If the volume of a container of gas is reduced, what will happen to the pressure inside the container?

1 Answer
Nov 28, 2016

Answer:

At constant #"temperature, " P_1V_1=P_2V_2#, which is #"Boyle's law"# and so.........

Explanation:

Pressure varies as the ratio #V_1/V_2#. If the gas were enclosed in a piston, the pressure should increase as the piston is compressed, and the pressure should decrease as the piston expands. This is intuitively sound.

Of course, we can combine with #"Charles' Law"# to give #(P_1V_1)/T_1=(P_2V_2)/T_2#, the combined gas law, and with #"Avogadro's law"#, #Vpropn#, to give the Ideal Gas law, #PV=nRT#, for an ideal gas.