# If there are 8.800 x 10^25 atoms of tin, how many moles is this, and what would be the mass?

Sep 2, 2016

$\text{1 mole}$ of tin has a mass of $118.71 \cdot g$; there are $6.022140857 \left(74\right) \times {10}^{23}$ individual atoms of tin in $1$ $m o l$

#### Explanation:

And thus,

$\text{Moles of tin}$ $=$ $\left(8.800 \times {10}^{25} {\text{ tin atoms")/(6.022xx10^23" tin atoms mol}}^{-} 1\right)$

$\cong$ $146 \cdot m o l$

And thus $\text{mass of tin atoms}$ $=$ $118.71 \cdot g \cdot m o {l}^{-} 1 \times 146 \cdot m o l$ $=$ $\text{over } 17 \cdot k g$ of tin metal.