If #w/x=y/z#, then what is the value of #x#?

1 Answer
Feb 20, 2017

First, multiply each side of the equation by #color(red)(x)color(blue)(z)# to eliminate the fractions while keeping the equation balanced:

#color(red)(x)color(blue)(z) xx w/x = color(red)(x)color(blue)(z) xx y/z#

#cancel(color(red)(x))color(blue)(z) xx w/color(red)(cancel(color(black)(x))) = color(red)(x)cancel(color(blue)(z)) xx y/color(blue)(cancel(color(black)(z)))#

#wz = xy#

Now, divide each side of the equation by #color(red)(y)# to solve for #x# while keeping the equation balanced:

#(wz)/color(red)(y) = (xy)/color(red)(y)#

#(wz)/y = (xcolor(red)(cancel(color(black)(y))))/cancel(color(red)(y))#

#(wz)/y = x#

#x = (wz)/y# When, #x != 0#, #z != 0#, #y != 0# and #(wz)/y != 0#