If water is added to 100.0 mL of a 0.150 M sodium hydroxide solution unit the final volume is 150.0 mL, what will the molarity of the diluted solution be?

1 Answer
Mar 15, 2017

Answer:

The end concentration will be...........#0.100*mol*L^-1#

Explanation:

#"Concentration"="Moles of solute"/"Volume of solution"#, i.e. #C=n/V#.

So #n=CV#.

Since here #n# is constant:

#C_1V_1=C_2V_2#

And #C_2=(C_1V_1)/V_2# (and the RHS clearly has the units of concentration, why?)

So #C_2=(100.0*cancel(mL)xx0.150*mol*L^-1)/(150*cancel(mL))=0.100*mol*L^-1#

Here, I did not have to convert the #mL# volume to litres, because these clearly cancel out in the calculation to give an answer in #mol*L^-1# as required.........