If water is added to 50 ml of a 0.04M solution so that it fills a 200 mL beaker, what is the final concentration?

1 Answer
Sep 28, 2016

Answer:

Final concentration #=# #0.01*mol*L^-1#.

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution in litres"#

#=# #(50xx10^-3*Lxx0.04*mol*L^-1)/(200xx10^-3L)#

#=# #(50xxcancel(10^-3)*cancelLxx0.04*mol*L^-1)/(200xxcancel(10^-3L))#

#=# #(1xxcancel(10^-3)*cancelLxx0.04*mol*L^-1)/(4xxcancel(10^-3L))#

#=# #0.01*mol*L^-1#