Question

If we take 2.2 grams of CO2; 6.02×10^21 atoms of nitrogen and 0.03 gram atoms of sulfer then what is the molar ratio of C,N and O respectively?

Answer 1

Well, we can ignore the sulfur….as it is NOT present in solution....(unless of course it was `SO_2`, but this is NOT specified.)

Explanation:

And so we got...

`chi_(CO_2)="moles of carbon dioxide"/"total moles in the gaseous solution"`

And we got with respect to dinitrogen...`(3.01xx10^21*"dinitrogen molecules")/(6.022xx10^23*"dinitrogen molecules"*mol^-1)=5.0xx10^-3*mol`

....WHY DID I HALVE THE GIVEN QUANTITY of nitrogen?

`chi_(CO_2)=((2.20*g)/(44.01*g*mol^-1))/((2.20*g)/(44.01*g*mol^-1)+(5.0xx10^-3*mol))=0.91`

And clearly, `chi_(N_2)=1-chi_(CO_2)=0.091`...