Question

If `x^2-(3a+b)x+6ab-2b^2=0` and `a-b=3`, so the value of `a` and `b` ?

Answer 1

See below.

Explanation:

Solving

`{(x^2-(3a+b)x+6ab-2b^2=0),(a-b=3):}`

for `a,b` we obtain

`{(a=1/2(x-3)),(b=1/2(x-9)):}` or

`{(a=1/2(x+6)),(b=x/2):}`