If x^2-(3a+b)x+6ab-2b^2=0 and a-b=3, so the value of "x" ?

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Answer 1 · 2017-10-15T08:42:13

#x^2-(3a+b)x+6ab-2b^2=0#
#a-b=3#

#x^2-(3a+b)x+6ab-2b^2#
#=x^2-3ax-bx+6ab-2b^2#
#=(x-2b)(x+b-3a)#

#a=3+b#

#=(x-2b)(x+b-3(3+b)#
#=(x-2b)(x+b-9-3b)#
#=(x-2b)(x-2b-9)#

#x=2b or x=2b+9#

Also, #b=a-3#

#=(x-2(a-3))(x+(a-3)-3a) #=(x-2a+6)(x-2a-3)#

#x=2a-6 or x=2a+3#

Therefore #x# an equal: