If #(x+2)# is a factor of #x^3-6x^2+kx+10#, what is k? Precalculus Real Zeros of Polynomials Synthetic Division 1 Answer Narad T. Jan 30, 2017 The answer is #k=-11# Explanation: Let #f(x)=x^3-6x^2+kx+10# If #(x+2)# is a factor Then, #f(-2)=0# #f(-2)=-8-24-2k+10=0# #2k=-22# #k=-11# Answer link Related questions What is synthetic division? What are common mistakes students make with synthetic division? How do I find the quotient and remainder using synthetic division? How do you write the remainder in synthetic division? How do I find the quotient #(x^3+5x^2+x-15)/(x+3)# by using synthetic division? How do I find the roots of a polynomial function by using synthetic division? How can synthetic division be used to factor a polynomial? How do I use synthetic division to find #p(-3)# for #p(x)=x^4-2x^3-4x+4#? Use synthetic division to find #p(4)# for #p(x)=x^4-2x^3-4x+4#? How do you use synthetic division to evaluate #f(3)# given that #f(x)=x^3+2x^2-7x+8#? See all questions in Synthetic Division Impact of this question 45040 views around the world You can reuse this answer Creative Commons License