If x=6 and y=-2, what is the value of #3xy+2x^2-y^3#?

1 Answer
Jan 10, 2017

Answer:

#44#

Explanation:

Substituting #color(red)(6)# for #x# and #color(blue)(-2)# for #y# gives:

#3color(red)(x)color(blue)(y) + 2color(red)(x)^2 - color(blue)(y)^3 ->#

#(3 xx color(red)(6) xx color(blue)(-2)) + (2 xx color(red)((6)^2)) - (color(blue)(-2))^3 ->#

#(-36) + (2 xx 36) - (-8) ->#

#-36 + 72 + 8 ->#

#44#