# If x=6 and y=-2, what is the value of 3xy+2x^2-y^3?

Jan 10, 2017

$44$

#### Explanation:

Substituting $\textcolor{red}{6}$ for $x$ and $\textcolor{b l u e}{- 2}$ for $y$ gives:

$3 \textcolor{red}{x} \textcolor{b l u e}{y} + 2 {\textcolor{red}{x}}^{2} - {\textcolor{b l u e}{y}}^{3} \to$

$\left(3 \times \textcolor{red}{6} \times \textcolor{b l u e}{- 2}\right) + \left(2 \times \textcolor{red}{{\left(6\right)}^{2}}\right) - {\left(\textcolor{b l u e}{- 2}\right)}^{3} \to$

$\left(- 36\right) + \left(2 \times 36\right) - \left(- 8\right) \to$

$- 36 + 72 + 8 \to$

$44$