If #x=8^(2/3)*32^-(5/2)# then find #x#?
3 Answers
See a solution process below:
Explanation:
Assuming the problem is:
First, use this rule of exponents to rewrite each term on the right side:
Next, use this rule of exponents to rewrite the
We can then use this rule to rewrite the exponents:
Now, use this rule to rewrite the denominator of the fraction:
Next, we can rationalize the fraction:
Or, approximately:
Using the law of indices:
Using the law of indices
Using the law of indices:
#x=(1/(2^10*sqrt2))
Rationalise
Explanation:
Both
Rationalise the denominator
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However, consider if the question had been: