If #xy=144#, #x+y=30#, and #x>y#, what is the value of #x-y#?

1 Answer
Feb 28, 2017

#x-y=color(green)(18)#

Explanation:

Given
[1]#color(white)("XXX")xy=144#
[2]#color(white)("XXX")x+y=30color(white)("X")rarrcolor(white)("X")y=30-x#

Substituting #(30-x)# for #y# back in [1]
[3]#color(white)("XXX")x(30-x)=144color(white)("X")rarrcolor(white)("X")x^2-30x+144=0#

Factoring
[4]#color(white)("XXXXXXXXXXXXXXXXX")(x-6)(x-24)=0#

Either #x=6# or #x=24#

[1] and [2] are symmetric, so whichever value is assigned to #x#, the other value is assigned to #y#

and since we are told #x > y#
#color(white)("XXX")rarr x=24 and y=6#

#rArr x-y = 24-6=18#