Question

If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?

Answer 1

The new concentration is `0.280*mol*L^-1` with respect to `LiCl`.

Explanation:

`"Concentration"` `=` `"Moles"/"Volume"`;

i.e. `C=n/V` or `n=CxxV`

So here, we calculate the initial molar quantity of lithium chloride, and then convert this to a concentration by dividing it by its new volume.

`(0.175*Lxx1.60*mol*L^-1)/(1.0*L)` `=` `0.280*mol*L^-1`.

What are the concentrations with respect to `Li^+` and `Cl^-`?