If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?

1 Answer
Oct 10, 2016

Answer:

The new concentration is #0.280*mol*L^-1# with respect to #LiCl#.

Explanation:

#"Concentration"# #=# #"Moles"/"Volume"#;

i.e. #C=n/V# or #n=CxxV#

So here, we calculate the initial molar quantity of lithium chloride, and then convert this to a concentration by dividing it by its new volume.

#(0.175*Lxx1.60*mol*L^-1)/(1.0*L)# #=# #0.280*mol*L^-1#.

What are the concentrations with respect to #Li^+# and #Cl^-#?