# If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?

Oct 10, 2016

The new concentration is $0.280 \cdot m o l \cdot {L}^{-} 1$ with respect to $L i C l$.

#### Explanation:

$\text{Concentration}$ $=$ $\text{Moles"/"Volume}$;

i.e. $C = \frac{n}{V}$ or $n = C \times V$

So here, we calculate the initial molar quantity of lithium chloride, and then convert this to a concentration by dividing it by its new volume.

$\frac{0.175 \cdot L \times 1.60 \cdot m o l \cdot {L}^{-} 1}{1.0 \cdot L}$ $=$ $0.280 \cdot m o l \cdot {L}^{-} 1$.

What are the concentrations with respect to $L {i}^{+}$ and $C {l}^{-}$?