If you flip a fair coin 4 times, what is the probability that you will get exactly 2 tails?
1 Answer
P("Exactly 2H") = 0.375 P(Exactly 2H)=0.375
Explanation:
Method 1 - Tree Diagram
P("Exactly 2H") = P("HHTT") + P("HTHT") + P(Exactly 2H)=P(HHTT)+P(HTHT)+
" " P("HTTH") + P("TTHH") + P(HTTH)+P(TTHH)+
" " P("THHT") + P("THTH") P(THHT)+P(THTH)
" " = 0.0625 * 6 =0.0625⋅6
" " = 0.375 =0.375
Method 1 - Combinations
Using the combination formula:
""_nC^r = ( (n), (r) ) = (n!)/(r!(n-r)!)
We seek any combination of 2 heads from 4 coins:
n("possible combinations") = ""_2C^4 = ( (4), (2) )
" " = (4!)/(2!(4-2)!)
" " = (4!)/(2!2!)
" " = (24)/(2*2)
" " = 6
And the total number of all combinations of 4 flips
n("total combinations") = 2^4
" " = 16
P("Exactly 2H") = 6/16
" " = 0.375