Question

If you have 12 mol FeCl3 and 12 mol O2, which would be the limiting reactant? (The equation is 4 FeCl3 + 3 O2 → 2 Fe2O3 + 6 Cl2)

Answer 1

The limiting reactant would be your `FeCl_3`.

This is because you need 4 of mol `FeCl_3` to produce 2 mol of `Fe_2O_3` while only 3 mol of `O_2` as the reaction proceed. So, you will exhaust first your `FeCl_3` supply, therefore making it your limiting reactant.