# If you have 3 mol of glucose in 6 L of solution, what is the molarity of the solution?

Apr 6, 2017

Why $0.5 \cdot m o l \cdot {L}^{-} 1$..............

#### Explanation:

$\text{Molarity"="Moles of solute"/"Volume of solution}$

And here, this quotient is $\frac{3 \cdot m o l}{6 \cdot L} = 0.5 \cdot m o l \cdot {L}^{-} 1$ WITH RESPECT to GLUCOSE.............

Given that glucose, ${C}_{6} {H}_{12} {O}_{6}$, has a molar mass of $180.2 \cdot g \cdot m o {l}^{-} 1$, what is the concentration of this solution with respect to $g \cdot {L}^{-} 1$?