If you have 3 mol of glucose in 6 L of solution, what is the molarity of the solution?

1 Answer
Apr 6, 2017

Answer:

Why #0.5*mol*L^-1#..............

Explanation:

#"Molarity"="Moles of solute"/"Volume of solution"#

And here, this quotient is #(3*mol)/(6*L)=0.5*mol*L^-1# WITH RESPECT to GLUCOSE.............

Given that glucose, #C_6H_12O_6#, has a molar mass of #180.2*g*mol^-1#, what is the concentration of this solution with respect to #g*L^-1#?