Question

In 68nm long DNA segment, 30% adenine is present, then calculate how many hydrogen bonds are present in this segment?

Answer 1

I get `40` hydrogen bonds.

Explanation:

Well, let's say that `30%` of adenine is present, and so there will be

`68 \ "nm"*30%=20.4 \ "nm"~~20 \ "nm"` of adenine bonds

Assuming each adenine bond takes up `1 \ "nm"`, then we have the following.

Adenine always pairs up with guanine in `"DNA"` bonding, as each of them have exactly `2` places to hydrogen bond with each other.

So, there will be a total of `2*20=40` hydrogen bonds in this segment.