In #7^(x+2)=343#, how do we solve for x?
1 Answer
Sep 12, 2017
Explanation:
#"note that "343=7^3#
#rArr7^(x+2)=7^3#
#"since both sides are "color(blue)"base 7"# we can equate the
exponents
#rArrx+2=3rArrx=3-2=1#
