Question

In a chemical equilibrium, the constant for backward reaction is 7.5 * 10^-4 and the equilibrium constant is 1.5. the rate constant for the forward reaction is..???

Answer 1

`1.125 × 10^-3`

Explanation:

Equilibrium constant `("K")` is given by

`"K" = ("K"_"f")/("K"_"b")`

`"K"_"f" = "K × K"_"b" = 1.5 xx 7.5 × 10^-4 = 1.125 × 10^-3`