In a experiment it is observed that 252 J of heat must be absorbed to raise the temperature of 50.0 g of Ni(s) from 20.0 C to 31.4 C. How do you calculate the specific heat of Ni in both J/g °C and cal/g.C?

1 Answer
Nov 24, 2016

Answer:

Using Joules, the specific heat of nickel is #0.442 "J"/("g"^@*"C")#.

Using calories, the specific heat of nickel is #0.106"cal"/("g"^@*"C")#. in calories.

Explanation:

The equation to use is #Q=mcDeltaT#, where #Q# is the energy in Joules, #m# is the mass, #c# is the specific heat, and #DeltaT# is the change in temperature. #DeltaT=T_"final"-T_"initial"#

#Q="252 J"#
#m="50.0 g"#
#DeltaT="31.4"^@"C"-"20.0"^@"C"="11.4"^@"C"#
#c=???#

Rearrange the equation to isolate #c#. Add the given values and solve.

#c=Q/(m*DeltaT)#

#c=(252"J")/((50.0"g")(11.4^@"C")##=0.442 "J"/("g"^@"C")#

Convert Joules to calories.

#"1 J=0.239"cal"#

#0.442cancel"J"xx(0.239"cal")/(1cancel"J")="0.106 cal"#

Using Joules, the specific heat of nickel is #0.442 "J"/("g"^@*"C")#.

Using calories, the specific heat of nickel is #0.106"cal"/("g"^@*"C")#. in calories.