In a new development, 50 one and two-bedroom condominiums were sold. Each one-bedroom condominium sold for $120 thousand and each two-bedroom condominium sold for $150 thousand. If sales totaled $7050 thousand, how many of each type of unit was sold?

2 Answers
Oct 27, 2017

15,35

Explanation:

Let no. of one bedrooms = x, then no. of two bedrooms = 50 - x.

Cost of x bedrooms @$120 = $120 x

Cost of 50 - x two bedrooms @$150 = $150(50 -x)

Now as per question,

rArr 120x + 150(50-x) = 7050

rArr 120x + 7500 - 150x = 7050

rArr -30x = 7050-7500 = -450

rArr x = (-450)/-30

rArr x = 15

So, no. of 1 bedrooms = 15 and no. of two bedrooms = 50 - 15 = 35.

Oct 27, 2017

In formula (t=number of two bedrooms, s=one-bedroom):
120s+150t=7050

Explanation:

Since s+t=50->s=50-t

Now substitute:
120(50-t)+150t=7050->
6000-120t+150t=7050->
Subtract 6000 from both sides:
cancel6000-cancel6000-120t+150t=7050-6000->
30t=1050->t=1050//30=35->s=50-35=15

Conclusion : 15 one-bedroom and 35 two-bedroom.

Check : 15xx120+35xx150=7050. Check!