In a thermometer the ice point is marked as #10# degree Celsius,and steam point as #130# degree Celsius .What will be the reading of this scale when it is actually #40# degree Celsius?

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Answer 1 · 2018-03-18T15:01:57

Relationship between two thermometer is given as,

#(C- 0)/(100-0)=(x-z)/(y-z)#

where, #z# is the ice point in the new scale and #y# is the steam point in it.

Given, #z=10^@C# and #y=130^@C#

so, for #C=40^@C#,

#40/100=(x-10)/(130-10)#

or,#x=58^@C#