In a TV set, an electron beam moves with horizontal velocity of 4.2 × 107 m/s across the cathode ray tube and strikes the screen, 41 cm away. The acceleration of gravity is 9.8 m/s How far does the electron beam fall while traversing this distance (in m)?
We can get the time of flight from the horizontal component, which is constant:
Now we can consider the vertical component:
This must be an old question as I don't think there are many cathode ray t.v sets around anymore.