In Exercise 9, what would the distance across the top of the worm thread have to be to make d equal to 0 inches? Trigonometry 1 Answer P dilip_k Jan 25, 2018 When d=0 inches the situation will be represented by the modified figure as shown above. The distance across the top of the worm thread then will be PR Now PR =2PQ= (2PQ)/(OQ)xxOQ =>PR = (2PQ)/(OQ)xx(QC+CQ) =>PR = (2PQ)/(OQ)xx(QC+(CQ)/(CN)xxCN) =>PR = (2PQ)/(OQ)xx(CN+(CQ)/(CN)xxCN) =>PR = (2PQ)/(OQ)xxCN(1+(CQ)/(CN)) =>PR = 2tanthetaxx0.75(1+csctheta) =>PR = 1.5(tantheta+tanthetaxxcsctheta) =>PR = 1.5(tantheta+sectheta) =>PR = 1.5(tan15^@+sec15^@)~~1.95 inch Answer link Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 1438 views around the world You can reuse this answer Creative Commons License