Question

In general form, write the equation of the line that is perpendicular to y=12 and passes through the point(-5,8)?

in general form, write the equation of the line that is perpendicular to y=12 and passes through the point(-5,8)?

Answer 1

x= -5

Explanation:

since y = 12 is a straight line parallel to the x-axis , then the equation of a line perpendicular to it must be parallel to the y-axis with equation x = a

In this case the line passes through (-5 , 8 ) hence a = - 5

hence equation is x = -5
graph{(y-12)(0.0001y-x-5)=0 [-32.03, 32.05, -16, 16.03]}