In one cycle, a heat engine takes in 810 J of heat from a high-temperature reservoir, releases some heat to a lower-temperature reservoir, and does 411 J of work. What is its efficiency?

1 Answer
Mar 1, 2018

#51%#

Explanation:

Coefficient of efficiency of a heat engine #eta = W/Q# (where, #W# is the work done by it and #Q# is the total heat taken from the heat source)

Given, #W=411J,Q=810J#

So, #eta = 411/810=0.51#

So,efficiency = #0.51*100 =51 %#