Question

In the equation `a-b+3i\sqrt5 = \sqrt5 + (a+b)i`, `a` and `b` are constants. If `i=\sqrt(-1)`, what is the value of `a^2 - b^2`?

Answer 1

`15`

Explanation:

Supposing that `a,b in RR` we have

`{(a-b=sqrt(5)),(a+b=3sqrt(5)):}`

so

`a^2-b^2=15`