Question

In the equation `Al_2(SO_4)_3 + 6NaOH -> 2Al(OH)_3 + 3Na_2SO_4`, what is the mole ratio of `NaOH` to `Al(OH)_3`?

Answer 1

3:1

Explanation:

The balanced equation will tell the stoichiometric ratio of reactants and products. Here in the balanced equation the coefficient before `NaOH` is 6 and that before `Al(OH)_3` is 2.
So the required mole ratio is 6:2=3:1