# In the equation Al_2(SO_4)_3 + 6NaOH -> 2Al(OH)_3 + 3Na_2SO_4, what is the mole ratio of NaOH to Al(OH)_3?

The balanced equation will tell the stoichiometric ratio of reactants and products. Here in the balanced equation the coefficient before $N a O H$ is 6 and that before $A l {\left(O H\right)}_{3}$ is 2.