In the equation #Al_2(SO_4)_3 + 6NaOH -> 2Al(OH)_3 + 3Na_2SO_4#, what is the mole ratio of #NaOH# to #Al(OH)_3#?

1 Answer
May 28, 2016

Answer:

3:1

Explanation:

The balanced equation will tell the stoichiometric ratio of reactants and products. Here in the balanced equation the coefficient before #NaOH# is 6 and that before #Al(OH)_3# is 2.
So the required mole ratio is 6:2=3:1