In the given figure of hydraulic press, if the cross section area of cylinder 'A' and 'B' are $0.5 m^{2}$ $0.5 m^2$ and $10 m^{2}$ $10 m^2$ respectively, what magnitude of effort is to be applied on cylinder 'A' to balance the load of $1000 N$ $1000N$ on cylinder 'B' ?

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Answer 1 · 2018-05-29T10:22:48

Let the magnitude of effort to be applied on cylinder 'A' to balance the load of
1000N on cylinder'B' be F N.

Now by Pascal's law the pressure on each piston will be same.

Hence

$\frac{Effort}{Area of A} = \frac{Load}{Area of B}$ $"Effort"/"Area of A"="Load"/"Area of B"$

$\Rightarrow \frac{F}{0.05} = \frac{1000}{10}$ $=>F/0.05=1000/10$

$\Rightarrow F = 0.05 \times 100 = 5 N$ $=>F=0.05xx100=5N$

In the given figure of hydraulic press, if the cross section area of cylinder 'A' and 'B' are 0.5 m^20.5m20.5 m^2 and 10 m^210m210 m^2 respectively, what magnitude of effort is to be applied on cylinder 'A' to balance the load of 1000N1000N1000N on cylinder 'B' ?