In the given figure of hydraulic press, if the cross section area of cylinder 'A' and 'B' are #0.5 m^2# and #10 m^2# respectively, what magnitude of effort is to be applied on cylinder 'A' to balance the load of #1000N# on cylinder 'B' ?

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1 Answer
P dilip_k
May 29, 2018

Let the magnitude of effort to be applied on cylinder 'A' to balance the load of
1000N on cylinder'B' be F N.

Now by Pascal's law the pressure on each piston will be same.

Hence

#"Effort"/"Area of A"="Load"/"Area of B"#

#=>F/0.05=1000/10#

#=>F=0.05xx100=5N#

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