Question

In the limit `lim 1/(10t)=oo` as `t->0^+`, how do you find `delta>0` such that whenever `0<t<delta`, `1/(10t)>100`?

Answer 1

See process below

Explanation:

Let be a `t>0`

We want `100<1/(10t)` that it's the same `1000t<1` or `t<1/1000`

Choosing `delta=1/1000>0` we get our goal

By one hand `t < delta`, by other hand `delta>0` and finally choosing `t < delta` (lets say `t=1/10000`) we get the result