# In the neutralization of sulfuric acid with sodium hydroxide, the theoretical yield from 6.9g of sulfuric acid is 10g. In a synthesis, the actual yield is 7.2g. What is the percentage yield for this synthesis?

Jan 3, 2017

%"Yield"="Mass recovered"/"Mass expected"xx100%

#### Explanation:

And thus for this example %"Yield" $=$ (7.2*g)/(10*g)xx100%

And we don't even need a calculator.........

Most of the time, we write a stoichiometric equation, that shows the molar equivalence between reactant and product, so that we can work out the limiting reagent etc.......

${H}_{2} S {O}_{4} \left(a q\right) + 2 N a O H \left(a q\right) \rightarrow N {a}_{2} S {O}_{4} \left(a q\right) + 2 {H}_{2} O$.

At any rate, you have not really quoted starting conditions here.