# In the reaction 4NH_3+6NO->5N_2+6H_2O, how many grams of ammonia will react with 27.8 grams of nitric oxide?

## The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

Aug 11, 2016

$\text{Approx. 10g ammonia will be consumed.}$

#### Explanation:

How many moles of nitric oxide reacted?

${n}_{\text{NO}}$ $=$ $\frac{27.8 \cdot g}{30.01 \cdot g \cdot m o {l}^{-} 1}$ $=$ $0.927 \cdot m o l$.

Your stoichiometric equation CLEARLY shows that each equiv $N O$ requires $\frac{2}{3} \text{ equiv}$ $\text{ammonia}$ for the comproportionation to occur.

Thus $\frac{2}{3} \times 0.927 \cdot m o l \times 17.0337 \cdot g \cdot m o {l}^{-} 1$ $=$ ??g