In this acid base reaction: #NaOH+HCl->NaCl+H_2O#, if we measured out 10.0 mL of a 2.0 M solution of #HCl#, how many grams of sodium hydroxide(#NaOH#; MW=40 g/mol) would we need to neutralize the #HCl# solution?
You have the stoichiometric equation. There is clearly 1:1 equivalence. Thus
It would be hard to measure such a quantity of sodium hydroxide as it is deliquescent, and once removed from the tin (or if the tin is poorly sealed), it would absorb moisture from the atmosphere.