In which of the following options is magnetic quantum number (m) = zero for all the three orbitals in a given option? A) 2s, 2px, 3dxy B) 3s, 2pz, 3dz^2 C) 2s, 2pz, 3dx^2 - y^2 D) 3s, 3px, 3dyz
1 Answer
Nov 24, 2017
B)
Explanation:
Magnetic quantum number is 0 for
#"s"# -orbital#"p"_z# orbital#"d"_(z^2)# orbital
[Note: 2. and 3. is valid only if z-axis is taken as ineternuclear axis.]