# In which quadrant does the graph of the sum of (-3 -5i) and (2+4i) lie?

Feb 20, 2016

#### Explanation:

$\left(- 3 - 5 i\right) + \left(2 + 4 i\right) =$
now gather the real and imaginary parts:
$\left(- 3 + 2\right) + \left(- 5 i + 4 i\right) =$
$- 1 - i$

Since both the real and the imaginary part of the result are negative, it lies in the $I I I$th quadrant (the bottom-left quadrant)

Remember:
$I = + +$
$I I = - +$
$I I I = - -$
$I V = + -$