Integrate e^1+cosx .sinx dx =?

inte^(1+cosx)sinx dx =?e1+cosxsinxdx=?

1 Answer
Jul 27, 2018

-e^(1+cosx)+C.e1+cosx+C.

Explanation:

Hoping that, the Question is to find I=inte^(1+cosx)sinxdxI=e1+cosxsinxdx,

let, (1+cosx)=u," so that, "-sinxdx=du(1+cosx)=u, so that, sinxdx=du.

:. I=-inte^(1+cosx)*(-sinxdx),

=-inte^udu,

=-e^u.

rArr I=-e^(1+cosx)+C.