Question

Integrate (sin 2pi*t)÷T from 0 to T÷2 ?

Answer 1

The answer `(-cos(2pit)-1)/(2pi)`

Explanation:

if your question was
`int_0^(t/2)sin2pit*dt`

`int_0^(t/2)sin2pit*dt=(-1/(2pi))int_0^(t/2)-2pi*sin(2pit)*dt`

`(-1/(2pi))[cos(2pi)]_0^(t/2)=(-cos(2pit)-1)/(2pi)`