Question

Integrate: (tanxsec^2x)dx Help!?

Answer 1

`inttan(x)sec^2(x)dx = 1/2tan^2(x)+C`

Explanation:

Given: `inttan(x)sec^2(x)dx`

Let `u = tan(x)`, then `du = sec^2(x)dx` and the integral becomes

`intudu = 1/2u^2+C`

Reverse the substitution:

`inttan(x)sec^2(x)dx = 1/2tan^2(x)+C`