Question

Integration of some trignometric functions ?

`int_0^(pi/2)(sinx + cosx)dx` = ?

Answer 1

`int_0^(pi/2)(sinx + cosx)dx=2`

Explanation:

show below

`int_0^(pi/2)(sinx + cosx)dx`

`[sin(x)-cos(x)]_0^(pi/2)=[sin(pi/2)-cos(pi/2)]-[sin(0)-cos(0)]`

`[1-0]-[0-1]=1+1=2`