Question

Iron reacts with dilute sulfaric acid according to equation, Fe+H2SO4---> FeSO4+H2, What mass of iron will react with 75cm3 of 0.5 M H2SO4?

Answer 1

2.1`grams` of `Fe`

Explanation:

C = `n/V`

This implies, n = C`*`V

n(H2SO4) = 0.5 `*` `75/1000` `dm^3`

n(H2SO4) = 0.0375 `mol`

from the chemical equation,

1`mol` of `Fe` reacts with 1`mol` of H2SO4

`therefore` 0.0375`mol` of H2SO4 will react with 0.0375`mol` of `Fe`

Also, n(`Fe`) = `(m(`Fe`)`/M(`Fe`))

M(`Fe`) = 56g/mol

m(`Fe`) = n(`Fe`)`*` M(`Fe`)

m(`Fe`) = 0.0375`*` 56

m(`Fe`) = `2.10grams`