Question

Is (6,1) (5,1) (4,1) (3,1) a function?

Answer 1

#(x,y) = {(6,1), (5,1), (4,1), (3,1)}
is a finite element function

Explanation:

Not value of `x` corresponds to more than one value of `y`;
therefore this is a function.

Note that it is not a continuous function; it exists only for the 4 elements of the specified domain.

Answer 2

Yes, the set `{ (6,1), (5, 1), (4, 1), (3, 1) }` is a function from the set `A = {3, 4, 5, 6}` to the set `B = {1}` that can be described by the formula `f(a) = 1` for all `a in A`

Explanation:

Let `A = { 3,4,5,6 }` and `B = { 1 }`.

Define `f(a) = 1` for all `a in A`

The domain of `f` is the whole of `A`. The range of `f` is the whole of `B`.

Then `f` can also be described fully by the set of pairs `{ (6,1), (5, 1), (4, 1), (3, 1) }`