Is #f(x)=sinx/x# increasing or decreasing at #x=pi/3#?

1 Answer
Apr 14, 2016

Decreasing.

Explanation:

To determine if a function is increasing or decreasing at a point, use the function's derivative:

  • If #f'(a)<0#, then #f# is decreasing at #x=a#.
  • If #f'(a)>0#, then #f# is increasing at #x=a#.

So, we first must find the derivative of #f#. To do so, we will have to use the quotient rule. Application of the quotient rule shows that

#f'(x)=(xd/dx(sinx)-sinxd/dx(x))/x^2#

#=(xcosx-sinx)/x^2#

So, to determine if #f# is increasing or decreasing at #x=pi/3#, find #f'(pi/3)# and see if it is positive or negative.

#f'(pi/3)=(pi/3cos(pi/3)-sin(pi/3))/(pi/3)^2#

#=(pi/3(1/2)-sqrt3/2)/(pi^2/9)approx-0.3123#

Since this is #<0#, the function is decreasing at #x=pi/3#.

We can check a graph of #f# #(#note that #pi/3approx1.0472)#.

graph{sinx/x [-3.945, 4.825, -1.568, 2.817]}