Is #f(x)=-x^3+3x^2-x+2# increasing or decreasing at #x=-1#?
1 Answer
Aug 15, 2016
decreasing at x = - 1
Explanation:
To determine if f(x) is increasing/decreasing at x = a, consider.
• If f'(a)> 0 , then f(x) is increasing at x = a
• If f'(a) < 0 , then f(x) is decreasing at x = a
differentiate using the
#color(blue)"power rule"#
#rArrf'(x)=-3x^2+6x-1#
#rArrf'(-1)=-3(-1)^2+6(-1)-1=-10# Since f'(-1) < 0 , then f(x) is decreasing at x = -1
graph{-x^3+3x^2+6x-1 [-50.76, 50.76, -25.4, 25.36]}